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Q:
Partial deconstruction in C++0x — what is the significance?
I have been reading about C++0x’s ability to partially deconstruct an object. Something like:
f(std::vector v{ 1, 2, 3, 4}).
If std::vector were a partially deconstructed object, the above code would call a constructor that takes four ints and pass them to a function f.
I know that in general partially deconstructed objects are a bad idea. However, I don’t see how the above partial deconstruction is harmful. Is there a reason for the fact that C++0x allows such partial deconstruction?
A:
std::vector v{ 1, 2, 3, 4} will not construct a std::vector object but std::vector{1, 2, 3, 4}. This is not a partiuclarly deconstructed object and is now a rvalue. It is legal to pass it to a function with a vector parameter.
A:
Because you have a fine example of what it does.
As some implementations of std::vector actually model a vector as an array, it will be even more obvious that it is not a “seperate constructor call” but a simple “invoke constructor”.
A:
It is only partially deconstructed, i.e. it has the same value a priori (before the function is called), but not its type. But it is not very useful, as the std::vector() constructor is a very thin layer, which merely passes the arguments on, without “fully” constructing the object.
From the C++03 standard draft:
If the argument is an lvalue, the constructor is invoked as if the object were default-constructed.
In C++0x, the draft says:
If the argument is an rvalue, the user-defined constructor is potentially invoked.
I.e. the constructor will not be invoked at all, if the argument is an rvalue.
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